At a given place on earth's surface the horizontal component of earths magnetic field is 2 × 10^-5 T and resultant magnetic field is 4 × 10^-5 T. The angle of dip at this place is?
![The value of horizontal component of the earth's magnetic field at a point is \\[0.5\\times {{10}^{-4}}\\text{tesla}\\] and the angle of dip is \\[\\text{45}{}^\\circ \\]. Find the value of vertical components.](https://www.vedantu.com/question-sets/932b2524-1834-4bc1-af87-9bb8910ffc48186918865695295683.png "The value of horizontal component of the earth's magnetic field at a point is \\[0.5\\times {{10}^{-4}}\\text{tesla}\\] and the angle of dip is \\[\\text{45}{}^\\circ \\]. Find the value of vertical components.")
The value of horizontal component of the earth's magnetic field at a point is \\[0.5\\times {{10}^{-4}}\\text{tesla}\\] and the angle of dip is \\[\\text{45}{}^\\circ \\]. Find the value of vertical components.
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